WebApr 12, 2024 · The synthesized biochar was physically activated at a temperature of 700 °C in an atmosphere of carbon dioxide. The flow of carbon dioxide was set to 100 mL/min. The heating temperature and gas flow remained constant for six hours. After the physical activation, the product was brought to room temperature under nitrogen . WebMay 19, 2024 · Volume of CO₂ Given: 200 gm of 50% pure CaCO₃ The correct answer is: (B) 22.4 litre Explanation: Equation: CaCO₃ ⇌ CaO + CO₂ One mole of calcium carbonate on …
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WebMar 26, 2024 · n × 22.4 L 1 m o l. 0.05 m o l × 22.4 L 1 m o l = 1.12 L. The volume of carbon dioxide obtained at STP is 1.12 l i t r e. So, the correct answer is Option B . Note: We must … WebCalculate the volume of CO2 (g) measured at STP that can be obtained by the thermal decomposition of CaCo3 by the equation. CaCo3 (g) --> CaO (g) + CO2 (g) Transcribed … scene t shirt clothing
Answered: Calculate the volume of CO2(g) measured… bartleby
WebThe atomic mass of CaCO3 is 100 gm/mol.So there is 0.04 mol of CaCO3. By heating 1 mol CaCO3 , we obtain 22,400 ml of CO2 at STP. So the volume that we obtain (of CO2) = 22400*0.04 = 896 ml. 4 More answers … WebSep 12, 2011 · Calculate the volume of CO2 produced at STP from the decomposition of 152 g calcium carbonate caco3? Wiki User ∙ 2011-09-12 14:27:26 Study now See answer (1) Best Answer Copy Molar mass CaCO3... WebSep 23, 2024 · Because the volume of carbon dioxide is measured at STP, the observed value can be converted directly into moles of carbon dioxide by dividing by 22.414 L mol … scene travel powered by expedia